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Sine Circle

Aug 25, 2021
2 min read

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Let's draw a circle with a radius of R

and mark out all the angles with a factor of 5 degrees around the circle as the diagram shown on the right.

now let's mark out all different radii with a length of (R x the sine of the angle the radius is pointing to) from the center.

you'll find that the tips of those radii are likely to form a circle, the target of this article is to prove that the tips of the radius are really forming a circle.











Proofing


first, let's name the important parts of the setup:

R is the length of the radius of the big circle,

R = a + b

θ is the angle which the radius is pointing to,

Rsinθ is the length of the dynamic radii you've drawn

​the angle p is the one attached to the "likely circle"

​

to prove the "likely circle" is a circle, we just need to prove the angle p is a right angle.


first we need to define the range of θ, α, and β

in this case


0° ≤ θ ≤ 180°

0° ≤ α ≤ 90°

0° ≤ β ≤ 90°


from the diagram, we know that


∵ cosα = a / Rsinθ ..... equation (1)

∴ a = R ⋅ sinθ ⋅ cosα


∵ tanα = h / a ..... equation (2)

∴ h = a ⋅ tanα


∵ α + θ = 90° ..... equation (3)

∴ sinα = cosθ

∴ cosα = sinθ


starting with


tanβ = h/b

tanβ = (a ⋅ tanα) / b ..... from equation (2)

tanβ = (a ⋅ sinα) / (b ⋅ cosα)

sinβ / cosβ = (R ⋅ sinθ ⋅ cosα ⋅ sinα) / (b ⋅ cosα) ..... from equation (1)

cosβ / sinβ = (b ⋅ cosα) / (R ⋅ sinθ ⋅ cosα ⋅ sinα)

b = (cosβ)(R ⋅ sinθ ⋅ cosα ⋅ sinα) / (sinβ ⋅ cosα)

b = (cosβ/sinβ) ⋅ R ⋅ sinθ ⋅ sinα ..... equation (4)


from


R = a + b

R = R ⋅ sinθ ⋅ cosα + (cosβ/sinβ) ⋅ R ⋅ sinθ ⋅ sinα ..... from equation (1) and equation (4)

1 = sinθ ⋅ cosα + (cosβ/sinβ) ⋅ sinθ ⋅ sinα

1 = sinθ ⋅ sinθ + (cosβ ⋅ sinθ ⋅ sinα)/sinβ

1 = sin²θ + (cosβ ⋅ sinθ ⋅ sinα)/sinβ

1 - sin²θ = (cosβ ⋅ sinθ ⋅ sinα)/sinβ

cos²θ = (cosβ ⋅ sinθ ⋅ cosθ)/sinβ ..... equation (3)

cosθ = (cosβ ⋅ sinθ)/sinβ

cosθ / sinθ = cosβ / sinβ

tanθ = tanβ

θ = β


from


α + β + p = 180°

α + θ + p = 180°

90° + p = 180°

p = 90° ..... (proofed)


Usage


by measuring the length of Rsinθ and R and a simple calculator,

we can calculate the value of sinθ approximately:​


the length of Rsinθ / the length of R = the value of sinθ

Comments


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